Identify the product formed in the above reac | vedclass

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(C) The reaction involves the treatment of a ketone with $D_2O$ in the presence of a base $(OH^-)$. This is an example of keto-enol tautomerism where

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(C) The reaction involves the treatment of a ketone with $D_2O$ in the presence of a base $(OH^-)$. This is an example of keto-enol tautomerism where the $\alpha$-hydrogens are acidic and can be exchanged with deuterium $(D)$ atoms. Since the reaction is carried out for a 'long time' in the presence of excess $D_2O$,all acidic hydrogens (including the $\alpha$-hydrogens of the ketones and the hydroxyl hydrogen of the alcohol group) will be replaced by deuterium atoms. The hydroxyl group $-OH$ will become $-OD$ due to rapid exchange with $D_2O$. Therefore,the final product will have all $\alpha$-hydrogens and the hydroxyl hydrogen replaced by deuterium.

List-$I$ Isomeric pairs	List-$II$ Type of isomers
$A$. Propanamine and $N$-Methylethanamine	$I$. Metamers
$B$. Hexan-$2$-one and Hexan-$3$-one	$II$. Positional isomers
$C$. Ethanamide and Hydroxyethanimine	$III$. Functional isomers
$D$. $o$-nitrophenol and $p$-nitrophenol	$IV$. Tautomers

Column-$I$	Column-$II$
$A$. Acetaldehyde,vinyl alcohol	$1$. Enantiomers
$B$. Eclipsed and staggered ethane	$2$. Tautomers
$C$. $(+)$$2$-butanol,$(-)$$2$-butanol	$3$. Chain isomers
$D$. Methyl-$n$-propylamine and diethylamine	$4$. Conformational isomers
	$5$. Metamers

Identify the product formed in the above reaction:

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